3 years ago

Which rule represents the translation from the pre image, rhombus ABCD, to the image rhombus A'B'C'D' ?

Mathematics

1 answer:

kvv77 [185]3 years ago

3 0

Answer:

Square ABCD was translated using the rule (x, y) → (x - 4, y + 15) to form A'B'C'D'.

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Answer:

The painting is 42.13 feet above the platform

Step-by-step explanation:

Refer the attached figure .

A particular painting forming an angle of 50 degrees with a camera platform .

∠ABC = 50°

We are also given that the light is 55 feet from the wall where the painting hangs

i.e. AB = 55 feet.

Now we are required to find how high above the platform is the painting. i.e. AC

So, we will use trigonometric ratio :

$sin\theta = \frac{Perpendicular}{Hypotenuse}$

$sin50^{circ} = \frac{AC}{AB}$

$sin50^{circ} = \frac{AC}{55}$

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$42.13= AC$

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