We will solve the equation:
x^2+5x-100≥0
![x_{12} = \frac{-5\pm \sqrt{25+400} }{2}= \frac{-5\pm20.6}{2}](https://tex.z-dn.net/?f=%20x_%7B12%7D%20%3D%20%5Cfrac%7B-5%5Cpm%20%5Csqrt%7B25%2B400%7D%20%7D%7B2%7D%3D%20%5Cfrac%7B-5%5Cpm20.6%7D%7B2%7D%20%20)
x1≈-12.8 x2≈ 7.8
It means that x∈ (-∞, -12.8 ) ∪ (7.8, +∞ ).
Answer:
C) x ≠ 7
Thank you.
B. 1.08mL
1 lb = 2.2 kg
5 lb = 2.27 kg
2.27kg × 12mg = 27.24 mg
Divide 27.42 mg by 2.5 = 10.896mg
Now change the mg to mL
10.896 ÷ 10 = 1.0896
<span>2x + 14 = 22
-14 -14
2x=8
/2 /2
x=4
4 is your answer.
Hoped I helped!
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Note that "Complement" = 90°, and "Supplementary" = 180°
Let the complement angle of 32 be x
x + 32 = 90
Isolate the x. Subtract 32 from both sides
x + 32 (-32) = 90 (-32)
x = 90 - 32
x = 58
D. 58° is your complement.
hope this helps