All you have to see whether or not a duplication mutation has occurred, is simply count the number of nucleotides present in the original DNA strand and compare that number to the nucleotides present in the options. The only sequence which has substantially more nucleotides would be C. Thus we know that certain portion had been duplicated if the sequence after the mutation is in fact C.
Answer:
C
Explanation:
i took the test.
if you subtract 108-72 you get 36 meaning 1 is 36.
I believe the answer is a) inside
Answer: Methionine-Alanine-Arginine-Lysine
Explanation: codon are tripple base code of nucleotide sequence specifying for a particular amino acid. There are 64 codons in all 61 determine a particular amino acid while 3 are stop codons. To start the translation process we have the start codon-AUG(methionine) and the three stop codon(UAA,UGA,UAG) which reads the end of translation.
For this sequence, AUGGCAAGAAAA
AUG- specifies Methionine the start codon
GCA- specify Alanine
AGA-specify Arginine
AAA- specify Lysine