Question

What is the general from of the equation of a circle with center at (a , b ) and radius of length m?

Answer 1

Answer:

$(x - a)^{2} + (y - b)^{2} = m^{2}$

Step-by-step explanation:

The equation of a circle has the following format:

$(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}$

In which r is the radius(half the diameter) and the centre is the point $(x_{0}, y_{0})$

In this question:

Center (a,b), so $x_{0} = a, y_{0} = b$

Radius m

Then

$(x - a)^{2} + (y - b)^{2} = m^{2}$