Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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the answer is D, you divide 8 by 16 you get 2 in below the division sign, cosine 180 is -1 , sine 180 is zero so the imaginary number cancels out leaving only -1 multiplied by 2 equals -2 then cosine and sine 95 equal negative the cosine and sine of 275 you take the negative sign common factor divide it by the negative sign of 2 and you get the answer is d
X=1/2 I’m mostly guessing but for math just use the app called photo math it’s helps with math equations but not math written problems
Marco spent more than $23. M > 23
We know the Kareem spent 8 less than Marco and that Kareem spent more than 15. If we add 8 onto the 15, we know that Marco has to be more than 23.
To graph this, draw an open circle at 23 and have an arrow going to the right.
