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zmey [24]
3 years ago
11

I am confused and need an answer ASAP.

Mathematics
1 answer:
Maurinko [17]3 years ago
8 0

Answer:

2 yes

Step-by-step explanation:

It's a right triangle so all the sides must be the same

(This is wrong D:)

Hope this helped! xox

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I can not see the image but if you write it I promise that I will answer it as quickly as possible

Step-by-step explanation:

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3 years ago
PLEASE HELP
valina [46]

Answer:

Step-by-step explanation:

You have 3 unknowns: a, b, and c.  It's our job to find them algebraically.  I'm going to start with the point where x = 0 and y = 7.  You'll see why in a minute.  Filling in the standard form of a quadratic

y=ax^2+bx+c  using (0, 7):

7=a(0)^2+b(0)+c  gives you that c = 7.  We will use that value now when we write the next 2 equations.  Now the point (-2, 19):

19=a(-2)^2+b(-2)+7  and

19=4a-2b+7 so

12 = 4a - 2b

Now for the next point (-1, 12):

12=a(-1)^2+b(-1)+7  and

12=a-b+7  so

5 = a - b

Now we have a system of equations (the 2 bold font equations) that we will solve by elimination:

 12  =  4a  -  2b

  5  =   a   -    b

Multiply the bottom equation by -4 to get a new system:

 12  =  4a  -  2b

-20  = -4a  +  4b

Add those together to get rid of the a terms and end up with

-8 = 2b so

b = -4

Now we can sub in -4 for b to solve for a.  I'm using the second bold type equation to do this:

5 = a - (-4) and

5 = a + 4 so

a = 1 and the equation for the quadratic function is

y=x^2-4x+7

7 0
3 years ago
Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and
Irina18 [472]

Answer: tea = 15 rupees  per kg

sugar= 3 rupees per kg

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997": </em>

2 t + 3 s =39 (a)

Where:

  • t= price of 1 kg of tea
  • s = price of 1 kg of sugar

<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "</em>

2(t1.25)+3(s1.2) = 48.30 (b)

  • <em>Solving for t in (b) </em>

2t =39-3s

t = (39 -3s)/2

t = 19.5-1.5s

  • <em>Replacing the value of t in (b) </em>

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

3 =s

  • <em>Replacing the value of s in (a) </em>

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.

4 0
3 years ago
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