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juin [17]
3 years ago
7

A bond analyst is analyzing the interest rates for equivalent municipal bonds issued by two different states. At α = 0.05, we wi

sh to test whether there is enough evidence to conclude that there is a difference in the interest rates paid by the two states. What is the value of the test statistic? State A State B Sample size 80 50 Mean interest rate (%) 4.0 4.5 Population variance 0.04 0.03
Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer: 15.08

Step-by-step explanation:

The test statistic for difference between two population means is given by :-

z=\dfrac{\overline{X}-\overline{Y}}{\sqrt{\dfrac{\sigma_x^2}{n_x}+\dfrac{\sigma_y^2}{n_y}}}

Given :                             State A   State B

Sample size                       80            50

Mean interest rate (%)        4.0           4.5

Population variance           0.04        0.03

Then , the test statistic for difference between two population means will be :-

z=\dfrac{4.0-4.5}{\sqrt{\dfrac{0.04}{80}+\dfrac{0.03}{50}}}\\\\\Rightarrow z=15.0755672289\approx15.08

Hence, the value of the test statistic will be 15.08 .

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a. P(24)=0.00007

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c. There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

Step-by-step explanation:

The probabilities of two events ("fire"and "theft") are compared to the probabilities of a certain number of days of rain during July.

The probabilities of "fire"and "theft" are around P=0.0001, and we need to calculate if the probability of exactly 23 and exactly 24 days of rain July have approximately the same probability.

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The probability of k days of rain is:

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For 24 days, the probability is:

P(24)=\frac{10^{24}e^{-10}}{24!}=\frac{1*10^{24}*4.54*10^{-5}}{6.20*10^{23}}  = 0.00007

The probability of 23 days of rain is 27% less than P=0.0001.

For 23 days of rain, the probability is:

P(23)=\frac{10^{23}e^{-10}}{23!}=\frac{1*10^{23}*4.54*10^{-5}}{2.59*10^{23}}  = 0.00018

The probability of 23 days of rain is 76% more than P=0.0001.

There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

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perimeter = 3 Km

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3 years ago
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