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Mandarinka [93]
3 years ago
9

The jar shown below is 2/5 filled with water. If 750 ml more water is poured into the jar, it becomes full. What is the capacity

of the jar?
2/5 is the fraction 2/5

Plz answer fast with easy explanation
Mathematics
2 answers:
iren2701 [21]3 years ago
6 0

Answer:

I’m glad you asked!

Step-by-step explanation:

2/5 + 750 ml equals the full jar amount or capacity.750/ 3 equals 250.That makes 150 the denominator.Now we just need to multiply 250 by 5.

250 x 5 = 1250.

serious [3.7K]3 years ago
5 0

Answer:

1250 ml

Step-by-step explanation:

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For the equation below, x is the input and y is the output. y = -4x + 3 If the input is -8, then the output is
KonstantinChe [14]

Answer:

35

Step-by-step explanation:

If is given the value -8 as it is the input then -->

y = -4(-8) + 3

Negative four times negative 8 is positive 32 so

y= 32 + 3

And 32 plus 3 is 35


7 0
3 years ago
Read 2 more answers
Will give brainliest
kodGreya [7K]

Answer: y=12 x =9

Step-by-step explanation:

In a parallelogram the diagonals bisect each other making them equal.

this means 2y + 6 = 30

we can rearrange this as 30 - 6 = 2y

24 = 2y  therefore y = 12

3x - 3 = 24

We can rearrange this as 24 + 3 = 3x

3x = 27

27 / 3 = 9

x = 9

Hope this helped :)

3 0
3 years ago
What is the completely factored form of f(x)=x^3-7x^2+2x+4
xxMikexx [17]

Solution, \mathrm{Factor}\:x^3-7x^2+2x+4:\quad \left(x-1\right)\left(x^2-6x-4\right)

Steps:

x^3-7x^2+2x+4

Use\:the\:rational\:root\:theorem,\\a_0=4,\:\quad a_n=1,\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1},\\\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x-1,\\\left(x-1\right)\frac{x^3-7x^2+2x+4}{x-1}

\frac{x^3-7x^2+2x+4}{x-1}

\mathrm{Divide}\:\frac{x^3-7x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^3-7x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{x^3}{x},\\\mathrm{Quotient}=x^2,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}x^2:\:x^3-x^2,\\\mathrm{Subtract\:}x^3-x^2\mathrm{\:from\:}x^3-7x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-6x^2+2x+4,\\Therefore,\\\frac{x^3-7x^2+2x+4}{x-1}=x^2+\frac{-6x^2+2x+4}{x-1}

\mathrm{Divide}\:\frac{-6x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-6x^2}{x}=-6x,\\\mathrm{Quotient}=-6x,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-6x:\:-6x^2+6x,\\\mathrm{Subtract\:}-6x^2+6x\mathrm{\:from\:}-6x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-4x+4,\\\mathrm{Therefore},\\\frac{-6x^2+2x+4}{x-1}=-6x+\frac{-4x+4}{x-1}

\mathrm{Divide}\:\frac{-4x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-4x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-4x}{x}=-4,\\\mathrm{Quotient}=-4,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-4:\:-4x+4,\\\mathrm{Subtract\:}-4x+4\mathrm{\:from\:}-4x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=0,\\\mathrm{Therefore},\\\frac{-4x+4}{x-1}=-4

\mathrm{The\:Correct\:Answer\:is\:\left(x-1\right)\left(x^2-6x-4\right)}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

8 0
3 years ago
what is 2+200 plz help btw who ever helps gets 21 pts and it is so easy i know the anwser i am just a bit bored so trying to giv
nlexa [21]
Its 202 becasue you just add two more so yeah 
5 0
4 years ago
Read 2 more answers
Change the fraction 3/4 to a percent
Rom4ik [11]
To convert 3/4 to a percent we need to convert 3/4 to a decimal and then multiply the decimal by 100. Lets do it:-

To convert a fraction to a decimal we have to divide the numerator by the denominator.

3/4  
3 ÷ 4 = 0.75

Decimal = 0.75

0.75 × 100 = 75
75%.

So, 3/4 in percent form is 75%.

Hope I helped ya!! xD 
6 0
4 years ago
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