In the slope-intercept equation for a line, the co-efficient of the x-term gives the _______

Mathematics

1 answer:

nignag [31]3 years ago

7 0

Answer:

slope

Step-by-step explanation:

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PLEASE HELP

Vlada [557]

Answer:

The equation is y = x + 9.

Step-by-step explanation:

We need to equation of SR

Slope = slope of UV = 3/2

= 1.

One point on SR is (-2, 7) so using the point-slope form of the equation:

y - y1 = m(x - x1)

Here m = 1, x1 = -2, y1 = 7:

y - 7 = 1(x - (-2))

y - 7 = x + 2

y = x + 9

7 0

2 years ago

Name the Property:

Kisachek [45]

multiplication property of equality

7 0

3 years ago

Someone can help??

oee [108]

Answer:

Step-by-step explanation:

let cos^{-1}x=t

cos t=x

when x=1,cos t=1=cos 0

t \rightarrow 0

$\lim_{x \to 1} \frac{1-\sqrt{x}}{(cos ^{-1}x)^2 } \\= \lim_{t \to 0} \frac{1-\sqrt{cos~t}}{t^2} \times \frac{1+\sqrt{cos~t}}{1+\sqrt{cos ~t}} \\= \lim_{t \to 0} \frac{1-cos~t}{t^2(1+\sqrt{cos~t})}} \\= \lim_{t \to 0 }\frac{2 sin^2~\frac{t}{2}}{t^2(1+\sqrt{cos~t})}} \\= 2\lim_{t \to 0 }(\frac{sin~t/2}{\frac{t}{2} })^2 \times \frac{1}{4} \times \lim_{t \to 0 }\frac{1}{1+\sqrt{cos~t}} \\=\frac{2}4} \times 1^2 \times \frac{1}{1+\sqrt{cos~0}} \\=\frac{1}{2} \times \frac{1}{1+1} \\=\frac{1}{4}$