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3 years ago

A chance with probability 1 is certain to happen true or false

1 answer:

3 0

Probability always adds up to 1 so, if there is only one choice, the chance that it will happen is 100% (1 out of 1) so true

Hope this helps! :)

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inessss [21]

The answer is 27 because the are nine options which can be recombined in 3 independent ways. Therefore, 9*3=27

7 0

3 years ago

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9) Gusnie uses

I am Lyosha [343]

Answer:

19,000.17 Cups

Step-by-step explanation:

im right ypur wrong

5 0

3 years ago

(1/27)^x-6=27 Could I please have a step by step as well? Much appreciated!

Andrei [34K]

Answer:

$x = 7$

Step-by-step explanation:

1) Use Division Distributive Property: (x/y)^a = x^a/y^a.

$\frac{1}{ {27}^{x - 8} } = 27$

2) Multiply both sides by 27^x - 8.

$1 = {27} \times 27^{1 + x - 8}$

3) Use the product rule: x^a x^b = x^a+b.

$1 = {27}^{1 + x - 8}$

4) Simplify 1 + x - 8 to x - 7.

$1 = {27}^{x - 7}$

5) Use Definition of Common Logarithm: b^a = x if and only if logb (x) = a.

$log_{27}1 = x - 7$

6) Use Change of Base Rule.

$\frac{ log_1 }{ log{27} } = x - 7$

7) Use rule of 1: log 1 = 0.

$\frac{0}{ log_{27}} = x - 7$

8) Simplify 0/log_27 to 0.

$0 = x - 7$

9) Add 7 to both sides.

$7 = x$

10) Switch sides.

$x = 7$

Therefor, the answer is x = 7.

5 0

3 years ago

A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 19 randomly selected pens yield

Romashka [77]

Given Information:

Probability of shipment accepted = p = 5%

Probability of shipment not accepted = q = 95%

Total number of pens = n = 19

Required Information:

Probability of shipment being accepted with no more than 2 defective pens = P( x ≤ 2) = ?

Answer:

P( x ≤ 2) = 0.933

Step-by-step explanation:

The given problem can be solved using Bernoulli distribution which is given by

P(n, x) = nCx pˣqⁿ⁻ˣ

The probability of no more than 2 defective pens means

P( x ≤ 2) = Probability of 0 defective pen + Probability of 1 defective pen + Probability of 2 defective pens

P( x ≤ 2) = P(0) + P(1) + P(2)

For P(0) we have p = 0.05, q = 0.95, n = 19 and x = 0

P(0) = 19C0(0.05)⁰(0.95)¹⁹

P(0) = (1)(1)(0.377)

P(0) = 0.377

For P(1) we have p = 0.05, q = 0.95, n = 19 and x = 1

P(1) = 19C1(0.05)¹(0.95)¹⁸

P(1) = (19)(0.05)(0.397)

P(1) = 0.377

For P(2) we have p = 0.05, q = 0.95, n = 19 and x = 2

P(2) = 19C2(0.05)²(0.95)¹⁷

P(2) = (171)(0.0025)(0.418)

P(2) = 0.179

Therefore, the required probability is

P( x ≤ 2) = P(0) + P(1) + P(2)

P( x ≤ 2) = 0.377 + 0.377 + 0.179

P( x ≤ 2) = 0.933

P( x ≤ 2) = 93.3%

Therefore, the probability that this shipment is accepted with no more than 2 defective pens is 0.933.

8 0

3 years ago

Factor completely: X^3-5x^2-9x+45

lesantik [10]

Answer:

x^2(3x-5)-9(x_5)

I think that is the answer and hope you will benefit from it

4 0

3 years ago

Read 2 more answers