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Ainat [17]
3 years ago
8

Ask the user to enter a number for red, green, and blue components of an RGB value. Test to make sure each value is between 0 an

d 255 inclusive. If a color's value is out of range, print which component is not correct (e.g., "Red number is not correct" if the red value is 300). Multiple colors may be out of range.
Computers and Technology
1 answer:
olganol [36]3 years ago
3 0

Answer:

  1. r = int(input("Enter a number for red channel: "))
  2. g = int(input("Enter a number for green channel: "))
  3. b = int(input("Enter a number for blue channel: "))  
  4. if(r < 0 or r >255):
  5.    print("Red number is not correct.")
  6. if(g < 0 or g >255):
  7.    print("Green number is not correct.")
  8. if(b < 0 or b >255):
  9.    print("Blue number is not correct.")

Explanation:

The solution code is written in Python.

Firstly, prompt user to input three numbers for red, green and blue (Line 1-3).

Next, create three similar if statements to check if the red, green and blue are within the range 0-255 by using logical operator "or" to check if the number is smaller than 0 or bigger than 255. If either one condition is met, display a message to indicate a particular color number is not correct (Line 5-12).

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Assoli18 [71]

The flowchart gives most of the solution, you only have to translate the loop to something like a while() { ... } structure:

X=0

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while (num > 5) {

ouput num

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num = num + 2

}

output X

If you run this with num = 8, it would print:

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4 0
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Answer:

See explaination

Explanation:

public class QuickRich {

static void getRichQuick() {

double amount = 1;

int day = 1;

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day++;

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7 0
4 years ago
Adios brainly, wont be posting that much take my points away i d c
mrs_skeptik [129]
Omg I would die to have your points because when I get on people call me a noob because I just got the app like 3 days ago and every time I answer a question some says noob like dang I just started
5 0
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Answer:

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