Answer:
x = 1
Step-by-step explanation:
In order to solve the given problem, we should have the knowledge of the following property.
- Measure of the tangents drawn from external points to a circle are equal.
46x - 1 = 45x
46 x - 45x = 1
x = 1
Answer:
Option (b) is correct.

Step-by-step explanation:
Given: 
We have too choose the correct simplification for the given statement.
Consider 
Using property of exponents,
We have,

Again applying property of exponents 
We have,

Simplify, we have,

we get,

Thus, 
Option (b) is correct.
<u><em>Answer:</em></u>
He read 1/3 of the book on the second day
He didn't finish the book in two days.
<u><em>Step-by-step explanation:</em></u>
Lets find 3/5 of 5/9
If we said, find 3/5 of x, the answer would be 3/5x.
3/5*x = 3/5x
In the same way, 
He read 1/3 of the book on the second day
Does 5/9 + 1/3 equal to 1?
1/3 = 3/9
5/9 + 3/9 = 8/9
He didn't finish the book in two days.
Hope this helps :)
Have a nice day!
Answer:
8 feet per second.
Step-by-step explanation:
We have been given that a car is driving away from a crosswalk. The formula
expresses the car's distance from the crosswalk in feet, d, in terms of the number of seconds, t, since the car started moving.
We will use average change formula to solve our given problem.





Therefore, the the car's average speed over the given interval of time would be 8 feet per second.
Answer:
Step-by-step explanation:
Hello!
The objective is to estimate the average time a student studies per week.
A sample of 8 students was taken and the time they spent studying in one week was recorded.
4.4, 5.2, 6.4, 6.8, 7.1, 7.3, 8.3, 8.4
n= 8
X[bar]= ∑X/n= 53.9/8= 6.7375 ≅ 6.74
S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/7*[376.75-(53.9²)/8]= 1.94
S= 1.39
Assuming that the variable "weekly time a student spends studying" has a normal distribution, since the sample is small, the statistic to use to perform the estimation is the student's t, the formula for the interval is:
X[bar] ±
* (S/√n)

6.74 ± 2.365 * (1.36/√8)
[5.6;7.88]
Using a confidence level of 95% you'd expect that the average time a student spends studying per week is contained by the interval [5.6;7.88]
I hope this helps!