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s2008m [1.1K]
3 years ago
15

Please help me answer this question

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0

Answer:

D

Step-by-step explanation:

y=x, x-axis, y=x, y-axis

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Cost to store: $140<br><br> Markup: 25%
anastassius [24]
The actual cost to the store = $140
Percentage of markup = 25%
Amount of markup in cost = (25/100) * 140 dollars
                                        = 35 dollars
Then
Sell price in the store = (35 + 140) dollars
                                   = 175 dollars
So the sell price of the product at the store after addition of the markup price will be $175.
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3 years ago
What would $25 deposited 56 yrs ago be worth today???
zhannawk [14.2K]
205 dollars today I think
7 0
4 years ago
One fourth of the 120 students took wood shop. How many students did not take wood shop?
yawa3891 [41]

Answer:

90 students.

Step-by-step explanation:

Given 1/4 of the 120 students took woodshop, just take the 3/4 that didn't take it:

\frac{3}{4}(120)

Find common factors between 4 and 120 to simplify, so 4.

\frac{3}{1} (30)

Now multiple across to get 90.

5 0
3 years ago
Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

5 0
3 years ago
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If you had a billion dollars and you waste half of your money how much would you Have plzz heart this
Ne4ueva [31]
You would have half a billion
4 0
3 years ago
Read 2 more answers
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