The required solution is ∠RQT = 202° and ∠QTS = 51°
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<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
brainly.com/question/14323008
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The formula of the surface area of the rectangular prism is equal:
where:
l - length
w - width
h - height
We have:
l = 5m
w = 8m
h = 9m
Substitute:
The first polynomial is 
The other polynomial is 
Now to add polynomials we must add or subtract like terms
Adding them we have
Here 
So we add then
We get
The addition of the polynomial is
7/8 .. *2 = 15/16
7/8 ...* 5 = 35/40
7/8 ...* 10 = 70/80
You can multiply the numerator and denominator by any number ( must be the same number), to result in an equivalent expression
5x + 55 <= 92.5
5x <= 92.5-55
5x <= 37.5 /: 5
x <= 7.5
