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bezimeni [28]
3 years ago
5

PLEASE HELP ASAP!!!!!!!!

Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0

Answer:

The first 5 terms are;

-2, 2, 13,38 and 91

Step-by-step explanation:

Here, we want to write the first 5 terms of the sequence.

We already have the first term as 1

Now, we need the 2nd term

Putting two in place of n, we have ;

2f(1) + 3n

= 2(-2) + 3(2) = -4 + 6 = 2

For the 3rd term, put 3 in place of n

2f(2) + 3(3)

sine f(2) = 2, we have

2(2) + 9 = 4+ 9 = 13

For the fourth term, put 4 in place of n, we have

2f(3) + 3(4)

since f(3) = 13

we have; 2(13) + 12 = 26 + 12 = 38

For the 5th term, put 5 in place of n, we have

2f(4) + 3(5)

since f(4) = 38, we have

2(38) + 15 = 76 + 15 = 91

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Point Q is the midpoint of AB. Q has coordinates of (-2, 4) and A has coordinates of (4,6). What are the coordinates of point B?
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Step-by-step explanation:

Let (x, y) be the coordinates of point B.

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We have 2(-2) = 4 + x and 2(4) = 6 + y.

Solving these, we get x = -8 and y = 2.

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Step-by-step explanation:

Here we want to know the next two numbers in the sequence.

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