Answer:
p = 5 and q = -3
Step-by-step explanation:
nth term = pn^2 + qn where n is the sequence number.
first term = p + q = 2.....................(1)
2nd term = p(2)^2 + 2n = 14
4p + 2q = 14
2p + q = 7 .......................(2)
Subtract equations (2) -(1) :-
p = 7 - 2 = 5
and q = 2 - 5 = -3
297 I think because 45+21=66, then x9= 594 divided by 2 is 297
Answer:
53 bulbs
Step-by-step explanation:
Answer:
The answer to the question would be D
