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MAXImum [283]
3 years ago
10

The radius of a spherical glass ornament is 6 centimeters. Twenty-seven ornaments are packed in a cube shaped box with a side le

ngth of 36 centimeters. What is the volume of the empty space in the box, rounded to the near whole number?
Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

45.413 cm³

Step-by-step explanation:

Because the volume of a orament is 57 cm³ . The volume of twenty-seven oraments is 1242 cm³ . The volume of a cube is 46656 cm³

⇒The empty space is :

         46656-1242=45414 ( cm³)

                  So the empty space is 45414 cm³  

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Would it be -1/3x -2?
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Why can't you use the product of powers rule to simplify<br> this expression? Explain.<br> 3^4.2^8
Tema [17]

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Because the base of this expression is not same.

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When a figure is translated, reflected, or rotated, what's the same about the original igure and its image? What's different?
Liula [17]

Answer:

The image of a translation, reflection, or rotation is congruent to the original figure, and the image of a dilation is similar to the original figure. Two figures are similar when one can be obtained from the other by a sequence of translations, reflections, rotations, and dilations.

7 0
3 years ago
a and b have the opposite directions. a has a magnitude of 7 , and b has a magnitude of 6 . What bust be true about a and b?
Hatshy [7]

Answer:

They are opposites and parallel.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.
Pachacha [2.7K]

a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

a)

The probability that the birth is a male can be written as

p(m) = 0.52 (which corresponds to 52%)

While the probability that the birth is a female can be written as

p(f) = 0.48 (which corresponds to 48%)

Here we want to calculate the probability that over  2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male  does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

p(mm)=p(m)\cdot p(m)

And substituting, we find

p(mm)=0.52\cdot 0.52 = 0.27

So, 27%.

b)

In this case, we want to find the probability that both children are female, so the probability

p(ff)

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

p(ff)=p(f)\cdot p(f)

And substituting

p(f)=0.48

We find:

p(ff)=0.48\cdot 0.48=0.23

Which means 23%.

c)

In this case, we want to find the probability they have exactly one male and exactly one female child. This is given by the sum of two probabilities:

- The probability that 1st child is a male and 2nd child is a female, namely p(mf)

- The probability that 1st child is a female and 2nd child is a male, namely p(fm)

So, this probability is

p(mf Ufm)=p(mf)+p(fm)

We have:

p(mf)=p(m)\cdot p(f)=0.52\cdot 0.48=0.25

p(fm)=p(f)\cdot p(m)=0.48\cdot 0.52=0.25

Therefore, this probability is

p(mfUfm)=0.25+0.25=0.50

So, 50%.

Learn more about probabilities:

brainly.com/question/5751004

brainly.com/question/6649771

brainly.com/question/8799684

brainly.com/question/7888686

#LearnwithBrainly

5 0
3 years ago
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