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4 years ago

A drawing has a scale of 1:40.

Mathematics

2 answers:

solmaris [256]4 years ago

8 0

Answer:

area of the kitchen

Step-by-step explanation:

in real life the dimensions are 10*40=400 cm=4 m and 18*40=720 cm=7.2 m

Area of the bedroom is A=4*7.2=28.8 m^2

Area of the kitchen is 300.000 cm^2=30 m^2

30>28.8

The bigger area is area of the kitchen

uranmaximum [27]4 years ago

4 0

Answer:

300,000 $cm^{2}$ is bigger

Step-by-step explanation:

10 x 40 = 400

18 x 40 = 720

400 x 720 = 288,000 $cm^{2}$ (area of the bedroom)

300,000 $cm^{2}$ is bigger by 12,000 $cm^{2}$ (so the kitchen is bigger)

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Helppp ya boyyyyyy!!!!!!!!!

Helen [10]

Answer:

866.64

Step-by-step explanation:

40/2 = 20

A = πr²

3.14*20² = 1256

52/2 = 26

3.14*26² = 2122.64

2122.64 - 1256 = 866.64

3 0

3 years ago

Read 2 more answers

The foci and the vertices of the hyperbola are labeled.<br> Which equation represents the hyperbola?

coldgirl [10]

Answer:

Correct option: first one -> (x+2)^2/64 - (y+4)^2/36 = 1

Step-by-step explanation:

The equation of the horizontal major axis hyperbola is:

(x-h)^2/a^2 - (y-k)^2/b^2 = 1

The center is located at (h,k), the vertices are (h+a,k) and (h-a,k) and the focuses are (h+c, k) and (h-c, k)

In this case, the vertices are (-10,-4) and (6,-4), so we have k = -4.

To find h and a, we have:

h+a = 6

h-a = -10

summing both equations, we have:

2h = -4

h = -2

and then for 'a':

-2+a = 6

a = 8

The focus it two units away from the vertix, so c = a + 2, then c = 10

To find b, we can use the relation c^2 = a^2 +b^2:

10^2 = 8^2 + b^2

b^2 = 100 - 64 = 36

b = 6

So the equation of the hyperbola is:

(x+2)^2/64 - (y+4)^2/36 = 1

Correct option: first one

8 0

3 years ago

Read 2 more answers

The weight of poodles at the dog pound are 22.1 , 24.3, 25.0, 27.1 , .30.0. What is the<br>mode?

Mekhanik [1.2K]

Answer:

None

Step-by-step explanation:

Because mode is a set of data values is the value that appears most often. If there is no data value or data values that occur most frequently, we say that the set of data values has no mode.

4 0

3 years ago

mr. huber bought a block of fudge that weighed 2/5 of a pound. he cut the fudge into 6 equal pieces. what was the weight of each

Marina86 [1]

Answer:

$\large \boxed{\frac{1}{15} \text{ lb}}$

Step-by-step explanation:

You are starting with ⅖ lb of fudge. Then you cut it into six pieces.

You want to evaluate ⅖ ÷ 6

1. Treat the integer as a fraction

$\dfrac{2}{5}\div{\dfrac{6}{1}}$

2. Invert the divisor and change divide to multiply

$\dfrac{2}{5}\times{\dfrac{1}{6}}$

3. Divide numerator and denominator by 2

$\dfrac{1}{5}\times{\dfrac{1}{3}}$

4. Multiply numerators and denominators

$\dfrac{1}{5}\times{\dfrac{1}{3}} = \mathbf{\dfrac{1}{15}}\\\\\text{Each piece of fudge weighs $\large \boxed{\mathbf{\frac{1}{15}} \textbf{ lb}}$}$

7 0

4 years ago

Determine where f(x) = x2 + 2x - 8 intersects the x-axis.

V125BC [204]

Let f(x) =0.
${x}^{2} + 2x - 8 = 0 \\ (x + 4)(x - 2) = 0 \\ x + 4 = 0 \\ x = - 4 \\ x - 2 = 0 \\ x = 2$
x=-4, 2

8 0

4 years ago