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2 years ago

The graph has lines that are what

Mathematics

2 answers:

pashok25 [27]2 years ago

6 0

Answer:

perpendicular

Step-by-step explanation:

solniwko [45]2 years ago

4 0

I believe you are looking for, intersecting.

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What is the unit rate of a graph

tiny-mole [99]

When you are looking for a unit rate in a graph you want to know how much the dependent (y) variable will increase by when the independent (x) variable is increased by one

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3 years ago

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How many equilateral triangles with sides of 4 can fit into a larger triangle with sides of 2012

igomit [66]

The base measures 2012 if you divide that by four you get 503 trianles on the bottom and on the sides and each one gets one smaller until you get to one so 503+502+501,.... or 252+251(504) so the answer is 126,756 triangles in total because 1+503=504 2+502=504... when you get to 252 you just add that to itself so that is the odd one out

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2 years ago

There is something wrong with the reason. I don’t know what it is. Could someone help me. The picture of the figure is on the ne

stira [4]

9514 1404 393

Answer:

CPCTC

Step-by-step explanation:

The applicable reason for statement 4 is "Corresponding Parts of Congruent Triangles are Congruent (CPCTC)".

The reason shown in your problem statement is applicable only within one triangle. The segments of interest are in two different triangles.

8 0

2 years ago

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Aisha needs to be at least 48 inches tall to ride the colossal coaster at the amusement park. If she grows 5 inches during the n

Anni [7]

X < 43, implies that the height of Aisha is less than 43 and can't be equal to 43 ( as there is no equal operator)

A is wrong as the inequality does not imply that Aisha is 0 tall , but any height height from 0 to 42.99999...

B) Correct , Aisha is not 43 and less she is less than that.

C) no, she may just need to grow 1 or 2 inches who knows.

D) nope, Aisha is at most 43 ( at least = 43 or taller)

at most 43 or less

4 0

2 years ago

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Find the x intercepts of the parabola with vertex (4,75) and y intercept (0,27)

user100 [1]

The equation for a parabola with vertex $(h, k)$ is
$y=a(x-h)^{2}+k$

We plug in:
$y=a(x-4)^{2}+75$

We find $a$ by plugging in the point $(0, 27)$ :
$27=a(0-4)^{2}+75$
$\Rightarrow 27=a(-4)^{2}+75$
$\Rightarrow 27=16a+75$
$\Rightarrow 16a=-48$
$\Rightarrow a=-3$

So our equation is
$y=-3(x-4)^{2}+75$

To find x-intercepts, we set $y=0$ :
$-3(x-4)^{2}+75=0$
$\Rightarrow -3(x-4)^{2}=-75$
$\Rightarrow (x-4)^{2}=25$
$\Rightarrow x-4=5, -5$
$\Rightarrow x=9, -1$

So the x-intercepts are 9 and -1.

8 0

2 years ago