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Maru [420]
3 years ago
6

Please help me please

Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Hello!

Inez walked in the treadmill for 7/10hr and had stopped for 1/2hr. How much time he was actually working out?

Time in the treadmill is \frac{7}{10} hr

1 hour is the whole, you can express it as \frac{10}{10}.

If you express it in minutes then \frac{10}{10} = 60min, then \frac{1}{10} = \frac{60}{10}= 6 min

Now you can calculate the amount of time he was on the treadmill:

\frac{7}{10}= 7*6= 42 min

Time he had stopped

\frac{1}{2}= 30min

Between the time he was on the treadmill and the time he rested, he worked out for 42 + 30= 72 min = 1 hour and 12 minutes.

During a 12- hour period, the temperature dropped 48 °C how many degrees did the temperature dropped each hour?

You can use cross multiplication to calculate how many degrees per hour the temperature decreased:

If in 12 hrs it decreased 48ºC

Then in 1 hr it decreased \frac{1*48}{12} = \\ 4ºC

The elevation of Turpan Pendi in China is -185 meters. The elevation of the Qattara Depression in Egypt is -163 meters. Compare the two elevations using < or >.______________

To easily determine which elevation is higher than the other you have to order them from least to greatest in a number line. These measurements are negative, which means that, the "higher" the module is, the less in the number line the negative value will be:

----|---------------------------------------|--------------------------------|--

-185                                        -163                                 0

(The line is not on scale)

Using < or >, you can say that  -163 meters > -185 meters.

I hope this helps!

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