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3 years ago

Is the following shape a rectangle

Mathematics

1 answer:

Gelneren [198K]3 years ago

4 0

Answer:

Step-by-step explanation:

no because the adjacent sides are not perpendicular.

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g A 5 foot tall man walks at 10 ft/s toward a street light that is 20 ft above the ground. What is the rate of change of the len

vredina [299]

Answer:

$-\frac{10}{3}ft/s$

Step-by-step explanation:

We are given that

Height of man=5 foot

$\frac{dy}{dt}=-10ft/s$

Height of street light=20ft

We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.

ABE and CDE are similar triangle because all right triangles are similar.

$\frac{20}{5}=\frac{x+y}{x}$

$4=\frac{x+y}{x}$

$4x=x+y$

$4x-x=y$

$3x=y$

$3\frac{dx}{dt}=\frac{dy}{dt}$

$\frac{dx}{dt}=\frac{1}{3}(-10)=-\frac{10}{3}ft/s=-\frac{10}{3}ft/s$

Hence, the rate of change of the length of his shadow when he is 25 ft from the street light= $-\frac{10}{3}ft/s$

7 0

3 years ago

14. Write an equation of the line using the slope and y-intercept. m = -5, b = -1

Paladinen [302]

Slope-intercept form: y = mx + b

The answer is:

y = -5x - 1

Happy to help!

4 0

3 years ago

Which expression is equivalent to

lutik1710 [3]

Answer:

$\frac{\sqrt[4]{3x^2} }{2y}$

Step-by-step explanation:

We can simplify the expression under the root first.

Remember to use $\frac{a^x}{a^y}=a^{x-y}$

Thus, we have:

$\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}$

We know 4th root can be written as "to the power 1/4th". Then we can use the property $(ab)^{x}=a^x b^x$

So we have:

$\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}$

Option D is right.

8 0

4 years ago

Who is faster? A girl who runs 200 meters in 28 seconds or her friend who runs 400 meters in 60 seconds? H.E.L.P

blagie [28]

Answer: The girl herself ran faster than her friend.

Step-by-step explanation:

This answer, of course assumes a lot of variables, but for the sake of keeping things simple, lets assume the following, the people are ran in a "straight line" with no "obstacles" in their way, and ran on the same track.

Calculating in meters-per-second for the girl who ran 200 meters in 28 seconds, you get 7.14285714286 meters per second

Calculating in meters-per-second for the girl who ran 400 meters in 60 seconds, you get 6.66666666667 meters per second

Comparing the two results, it can be "accurately" concluded that the girl herself ran faster than her friend under the following assumptions earlier stated.

4 0

3 years ago

Im blue what can i do

Radda [10]

Answer:

first, you can go to the doctor

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers