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SVETLANKA909090 [29]
2 years ago
8

In how many ways can a team of 8 people be selected from 5 women and 10 men?

Mathematics
1 answer:
zzz [600]2 years ago
6 0

Answer:

6435 ways

Step-by-step explanation:

Since the order does not matter, it is a combination, also because they do not indicate how many men and how many women should be in the group of 8, which means that it would be the ways of putting together a group of 8 with 15 people (10 men + 5 women)

That is to say:

nCr = n! / (r! * (n-r)!)

n = 15, r = 8, replacing:

15C8 = 15! / (8! * (15-8)!)

15C8 = 6435

which means that there are 6435 ways to arm the group

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Which of the following is a solution to 2cos2x − cos x − 1 = 0?
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Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





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