Answer:
$0 < p ≤ $25
Step-by-step explanation:
We know that coach Rivas can spend up to $750 on 30 swimsuits.
This means that the maximum cost that the coach can afford to pay is $750, then if the cost for the 30 swimsuits is C, we have the inequality:
C ≤ $750
Now, if each swimsuit costs p, then 30 of them costs 30 times p, then the cost of the swimsuits is:
C = 30*p
Then we have the inequality:
30*p ≤ $750.
To find the possible values of p, we just need to isolate p in one side of the inequality.
So we can divide both sides by 30 to get:
(30*p)/30 ≤ $750/30
p ≤ $25
And we also should add the restriction:
$0 < p ≤ $25
Because a swimsuit can not cost 0 dollars or less than that.
Then the inequality that represents the possible values of p is:
$0 < p ≤ $25
A linear inequality to represent the algebraic expression is given as 492.46 - x ≥ 500
<h3>Linear Inequality</h3>
Linear inequalities are inequalities that involve at least one linear algebraic expression, that is, a polynomial of degree 1 is compared with another algebraic expression of degree less than or equal to 1.
In this problem, her minimum balance must not decrease beyond $500 or she will pay a fee.
where
The inequality to represent this can be written as
524.96 - 32.50 - x ≥ 500
Simplifying this;
492.46 - x ≥ 500
The linear inequality is 492.46 - x ≥ 500
Learn more on linear inequality here;
brainly.com/question/23093488
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Answer:
monomial
Step-by-step explanation:
For the first one a = 2.5. For the second one m = 4. For the third one m = -4
