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4 years ago

Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .

Mathematics

1 answer:

sergey [27]4 years ago

8 0

Step 1) Divide the figure into separate shapes

Long rectangle: 27 x 5

Triangle: 3 x 4

Middle rectangle: 15 x 7

Small rectangle: 6 x 3

Step 2) Find the area of each shape

Long rectangle: A = 27 x 5 = 135

Triangle: A = 1/2 x 3 x 4 = 6

Middle rectangle: A = 15 x 7 = 105

Small rectangle: 6 x 3 = 18

Step 3) Add all of the areas together

A = 135 + 6 + 105 + 18 = 264 square feet

Hope this helps! :)

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Step-by-step explanation:

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3 years ago

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3 years ago

The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial

xxTIMURxx [149]

Step-by-step explanation:

Let the initial population of a community be P0 and the population after time t is P(t).

If the population of a community is known to increase at a rate proportional to the number of people present at time t, this is expressed as:

$P(t) = P_0e^{kt}$

at t = 5 years, P(t) = 2P0

substitute:

$2P_0 = P_0e^{5k}\\2 = e^{5k}\\ln2 = lne^{5k}\\ln2 = 5k\\k = \frac{ln2}{5}\\k = 0.1386$

If the population is 9,000 after 3 years

at t = 3, P(t) = 9000

a) Substitute into the formula to get P0

$9000 = P_0e^{0.1386\times 3}\\9000 = P_0e^{0.4158}\\9000 = 1.5156P_0\\P_0 = \frac{9000}{1.5156}\\ P_0 = 5938.24$

Hence the initial population is approximately 5938.

b) In order to know how fast the population growing at t = 10, we will substitute t = 10 into the formula as shown:

$P(10) = 5938.24e^{0.1386(10)}\\P(10) = 5938.24e^{1.386}\\P(10) = 5938.24(3.9988)\\P(10) = 23,745.97$

Hence the population of the community after 10 years is approximately 23,746

4 0

4 years ago