Answer:
3927 cm² wrapping paper will be required.
Step-by-step explanation:
Lateral surface area of a cone shaped wrapper = πrl
where, r = radius of the waffle cone
and l = slant height of the cone
It has been given in the question, radius 'r' = 5cm
and lateral height 'l' = 10 cm
Lateral surface area of the cone = π(5)(10)
= 50π
= 157.08 cm²
If they plan to make 25 waffles then wrapper paper required
= 25×157.08
= 3927 cm²
Therefore, 3927 cm² wrapping paper will be required.
Answer:
I can even see anything can you reupload your answer, please?
Step-by-step explanation:
Answer:
x = -3 and x = -3/2
Step-by-step explanation:
After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:
p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>
p(x) = x^2(2x+3) <u>-9(2x+3)</u>
Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:
p(x) = (x^2 - 9)(2x+3)
Factor it once more because there's a difference of squares:
p(x) = (x+3)(x-3)(2x+3)
Now just plug in whatever makes the each bracket equal 0:
x = -3, x = 3, and x = -3/2
Those are your zeros.
