Answer:
The amount invested at 3% is 300 &
The amount invested at 2% is 100.
Step-by-step explanation:
Total yearly interest for the two accounts is: $11
Let x be the amount invested at 3%
& y be the amount invested at 2%
From the question we can get 2 equations as;
x = 3y --------------------------Equation 1
0.03x + 0.02y = 11 ----------Equation 2
Substitute for x in Equation 2 we get;
0.03 (3y) + 0.02y = 11
0.09y + 0.02y = 11
0.11y = 11
Divide the above equation by 0.11, we get;
y = 
y = 100
Let us substitute the value of y in Equation 1 we get;
x = 3(100)
x = 300
Now to check our answer let us put in the simple interest formula. If we get the sum of the two interests equal to 11 then our answers are correct:
0.03 x 300 + 0.02 x 100
= 9 + 2
= 11
Hence the amount invested at 3% is 300 and the amount invested at 2% is 100.
Answer:
|x-153|=57
Step-by-step explanation:
edmentum
Answer:
36
Step-by-step explanation:
Since f(x) varies directly with x, f(x) can be expressed alternatively as \[f(x) = k * x\] where k is a constant value.
Given that f(x) is 72 when the value of x is 6.
This implies, \[72 = k * 6\]
Simplifying and rearranging the equation to find the value of k:
k = \frac{72}{6}
Hence k = 12
Or, \[f(x) = 12 * x\]
When x = 3, \[f(x) = 12 *3 \]
Or in other words, the value of f(x) when x=3 is 36
Answer:
None of the options is correct
Step-by-step explanation:
It is important to know that he expression a < x < b means that x is greater than a and less than b. So, for finding the correct value let's analyse each option.
A. 4 < 50 < 5
50 is greater than 4 but it is not less than 5, so, option A is incorrect.
B. 7 < 50 < 8
50 is greater than 7 but it is not less than 8, so, option B is incorrect.
C. 8 < 50 < 9
50 is greater than 8 but it is not less than 9, so, option C is incorrect.
D. 10 < 50 < 11
50 is greater than 10 but it is not less than 11, so, option D is incorrect.
Thus, none of the options is correct.
Y=10x+20
10x because the price is $10 a class
+20 because it costs $20 for the monthly subscription
