Question

Write an equation in point-slope form of the line that passes through (3, -8) and (7,-2).

Answer 1

Answer:

A line that passes through (3, -8) and (7,-2).

Denote equation of that line: y = ax + b

=> Slope a can be directly determined by:

a = (7 - 3)/(-2 - -8) = 4/6 = 2/3

=> y = (2/3)x + b

This line passes (3, -8), then: -8 = (2/3)*3 + b => -8 = 2 + b => b = -10

=> y =(2/3)x - 10

There are other ways to find equation of line.

Hope this helps!

:)

Answer 2

Answer:

$\frac{3}{2} x+10$

Step-by-step explanation:

$\frac{y1 - y2}{x1 - x2} \\ \frac{ - 8 - ( - 2)}{3 - 7} \\ \frac{ - 8 + 2}{ - 4} \\ \frac{ - 6}{ - 4} \\ = \frac{3}{2}$

y=3/2x+c

-8-3/2=c

c=10