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yan [13]
3 years ago
5

(8^4)(6^3)(16^-2)÷32

Mathematics
2 answers:
maria [59]3 years ago
8 0

Answer:

(3/2)^3

Step-by-step explanation:

The trick here is to identify the common base (it is 2) and express all factors except for 3^2 as powers of 2 that can be added or subtracted.

Note that 8 = 2^3, 6 = 2 * 3, 16 = 2^4 and 32 = 2^5.  Using this info, we can immediately begin reducing the given expression:

                                         (2^3)(2^3)(3^3)        2^6*3^3             3^3

(8^4)(6^3)(16^-2)÷32  =>  ----------------------- = ----------------  =  --------------

                                          2^4*2^5                 2^9                   2^3                                      

                                           

                                                                                               = (3/2)^3

Taya2010 [7]3 years ago
6 0

Answer:

108

Step-by-step explanation:

8^4 = 4096

6^3 = 216

16^-2 = 0.00390625

4096x216x0.00390625 = 3456

3456/32 = 108

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