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2 years ago

What is the length of the diagonal, d, of the rectangular prism shown below?

Mathematics

2 answers:

bearhunter [10]2 years ago

5 0

Answer:

10 (8.06)

Step-by-step explanation:

H^2 = p^2 + B^2

H^2 = (7^2) + (4^2)

= $\sqrt{65\\$

= 0.8622

round off to 10

Pani-rosa [81]2 years ago

4 0

Answer:

The answer is 8.3

Step-by-step explanation:

(I'm not that good at explaining things so bear with me please. I checked on Khan Academy so it's right)

I split the box on the right diagonally and got the equation

$4^{2}$ + $2^{2}$ = $x^{2}$

=16 + 4 = $\sqrt{20}$

≈4.5

The new triangle will help solve what d is

$4.5^{2}$ + $7^{2}$ = $d^{2}$

=20.25 +49 = $\sqrt{69.25}$

≈8.3

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Calls to a customer service center last on average 2.8 minutes with a standard deviation of 1.4 minutes. An operator in the call

Natali5045456 [20]

Answer:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n-values of normal variable:

Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is $M = n\mu$ and the standard deviation is $s = \sigma\sqrt{n}$

Calls to a customer service center last on average 2.8 minutes.

This means that $\mu = 2.8$

75 calls each day.

This means that $n = 75$

What is the expected total amount of time in minutes the operator will spend on the calls each day

This is M, so:

$M = n\mu = 75*2.8 = 210$

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

6 0

2 years ago

Please give answer of 6 number

Irina18 [472]

Answer:

$7,500$

Step-by-step explanation:

Let's solve this problem step-by-step. The library had 1,500 books in 2011. The ratio of books in 2011 and in 2012 is 1:2. Therefore, let the number of books in 2012 be $x$ .