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DanielleElmas [232]
3 years ago
7

Please solve this question fast.

Mathematics
1 answer:
Alexxandr [17]3 years ago
3 0

Answer:

See Explanation

Step-by-step explanation:

{a} =  {6}^{x},  \:  \: b = {6}^{y}  ...(given) \\  {a}^{y}. {b}^{x}  = 36..(1) \\ pluggig \: the \: values \: of \: a \: and \: b \: in \: (1) \\  ({6}^{x}) ^{y} . ({6}^{y}) ^{x} =  {6}^{2}  \\ {6}^{xy}.{6}^{xy} =  {6}^{2}  \\  {6}^{xy + xy}  =  {6}^{2}  \\  {6}^{2xy}  =  {6}^{2}  \\ bases \: are \: equal \: so \: exponentes \: will \: also \: be\\ \: equal \\  \therefore \: 2xy = 2 \\ xy =  \frac{2}{2}  \\ \huge \red { \boxed{ xy = 1}} \\ hence \: proved \\

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