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Dovator [93]
3 years ago
6

Given a circle U which has a center at coordinates (1,3) and a point on its circumference at (2, 2), what is the area of the cir

cle?
A.)6.3 units squared
B.)8.8 units squared
C.)10.5 units squared
D.)12.4 units squared
Mathematics
1 answer:
dalvyx [7]3 years ago
8 0
The answer is b.) sorry if I’m wrong but I did the work and got b.)
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On the weekdays a grocery store has 14239 customers and on the weekends the grocery store has
Vedmedyk [2.9K]

Answer: 2605 more on weekdays

Step-by-step explanation:

14239 - 11634 = 2605

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1 year ago
Jeremy is the oldest of four brothers. Each of the four boys gets an allowance for doing chores at home each week. The amount of
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$12.75-$11.25= $1.50, $9.75-$1.50= $8.25 his little brother should get $8.25 hope it helps
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3 years ago
Multiply. Write your answer as a fraction in the simplest form.<br> (−1 2/3)^3
nikdorinn [45]

Answer:

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If yvaries inversely as x and y=18 when x=2, find y when x=4
Sergio039 [100]

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7 0
4 years ago
1) Jo Anne needs to do a speech in her English class that can't be more than 4 minutes
djyliett [7]

Answer:

( 0 < y < 23 / 6 ) mins

Step-by-step explanation:

Solution:-

We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.

The time taken to give her speech must always be less than 4 minutes. We can express this mathematically using an inequality as follows:

                              ( 0 < x < 4 ) minutes

Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:

                             10 s * \frac{min}{60 s}  = \frac{1}{6} min

The time taken by Jo Anne to complete her speech in English class can be represented as:

                             y = x - 1/6

Using the range of time that Jo Anne could take in delivering her speech in the class would be:

                                    0 < x < 4

                            0 - 1/6 < y < 4 - 1/6

                            -1/6 < y < 23 / 6

Since time can not be less than zero. We correct the lower limit to " 0 " as follows:

                              ( 0 < y < 23 / 6 ) mins

   

7 0
3 years ago
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