All categories

3 years ago

Solve 2x ≤30 round to the nearest ten thousand

Mathematics

1 answer:

Sliva [168]3 years ago

5 0

Answer:

x ≤15

Step-by-step explanation:

2x ≤30

Divide each side by 2

2x/2 ≤30/2

x ≤15

You might be interested in

Brendan has 33 coins in his pocket, all of which are dimes and quarters. if the total value of his change is 615 cents, how many

Amanda [17]

If all were dimes, the value would be $3.30. Brendan has $2.85 more than that. Each quarter that replaces a dime increases the value by $0.15, so Brendan must have $2.85/$0.15 = 19 quarters.

Brendan has 14 dimes and 19 quarters.

6 0

3 years ago

Which answer BEST describes the solution for x if – 3 < x + 4 ≤ 7?

Mama L [17]

C is the answer look at the way I. form is

8 0

3 years ago

Read 2 more answers

Find the tangent line equation of the curve at the given point. Y=arcsin(7x) at the point where x=sqrt2/14

Mumz [18]

Answer:

$Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})$

Step-by-step explanation:

The equation of the curve is

$Y = sin^{-1}(7x)$

To find the equation of tangent we need to differentiate this equation w.r.t x

So, differentiating we get

$Y'=\frac{7}{\sqrt{1-49x^2} }$

This would give the slope of the tangent line at any given point of which x coordinate is known. In the present case it is $x = \sqrt{\frac{1}{7} }$

Then slope would accordingly be

$Y'=\frac{7}{\sqrt{1-49/49} }$

= ∞

For, $x = \sqrt{\frac{1}{7} }$ , $Y = sin^{-1}(7/7)= \pi/2$

Equation of tangent line, in the point slope form, would be $Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})$

4 0

3 years ago

Consider the equation:

Alenkasestr [34]

Answer:

the equation is not correct....

well, it should look sth. like (x+or- number)^2=number

5 0

3 years ago

For g(x)=3x+1, determine g(3-2x)

wolverine [178]

Answer:

g(3−2x)=12x2−36x+29

Step-by-step explanation:

Do you need step by step?

5 0

3 years ago