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aniked [119]
3 years ago
9

Simplify the expression:

Mathematics
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

235a is 1

235b is a^12k+4 i think

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Line AB contains (0, 4) and (1, 6) Line CD contains points (2, 10) and (−1, 4). Lines AB and CD are
vlada-n [284]

Answer  

Option (A) is correct .

Reason

The formula for the slope.

Slope = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}

As given

Line AB contains (0, 4) and (1, 6) .

put in the slope formula

Slope = \frac{6 - 4}{1 - 0}

Slope = \frac{2}{1}

Slope of the AB is 2.

As given

Line CD contains points (2, 10) and (−1, 4).

put in the slope formula

Slope = \frac{4 - 10}{-1 -2}

Slope = \frac{-6}{-3}

Slope = 2

Slope of the CD is 2.

As the slope of the  AB contains (0, 4) and (1, 6) Line CD contains points (2, 10) and (−1, 4) is 2 .

Therefore the option (A) is correct i.e the lines are parallel because the slopes are the same.

5 0
3 years ago
Read 2 more answers
the late fee for library books is $2.00 plus 15c each day for a book that is late. if monica's late fee is $2.75, write and solv
OLga [1]

Answer: .15x+2.00= 2.75

x=5


Step-by-step explanation:

2.75-2.00= .75

.75/.15= 5


Therefor Monica's book is 5 days late


4 0
4 years ago
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Solve −h−7h+13=3. Solve for h
Andreyy89

Answer:

I think your answer is h = -1

6 0
3 years ago
Read 2 more answers
What are the factors of 21?
Genrish500 [490]
The factors 1 ,3 ,7 ,21
3 0
3 years ago
A cylinder has a height of 8.1 inches and circular base with a diameter of 2.7 inches. The cylinder contains 3 green spheres, ea
klasskru [66]

Answer:

A point is chosen at random inside the cylinder, then probability the point belongs outside of the spheres is 0.25

Step-by-step explanation:

Let's find volume of the cylinder and volume of the three spheres.

Volume of cylinder =\pi r^{2} h

Volume of sphere =\frac{4}{3} \pi r^{3}

Now, r =2.7

h=8.1

Find volume of each shape.

Volume of cylinder =\pi (2.7)^{2} (8.1)

                             =59.049\pi

Now, volume of 3 spheres =3*\frac{4}{3} *\pi *(2.7)^{3}

                                         =78.732\pi

Now, p(E)=\frac{Outcomes favorable to event E}{Total number of outcomes}

So, Probability of point is chosen at random inside the cylinder which belongs outside of the spheres  is

                  \frac{78.732\pi -59.049\pi }{78.732\pi }

Let's simplify them

             0.25

A point is chosen at random inside the cylinder, then probability the point belongs outside of the spheres is 0.25

6 0
3 years ago
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