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3 years ago

15

1/2(x + 1)²- 3

1 answer:

Ierofanga [76]3 years ago

4 0

Answer:

a = 1/2
h = -1
k = -3

Step-by-step explanation:

We assume you want to compare your expression to the form ...

a(x -h)² +k

1/2(x +1)² +k

The multiplier outside parentheses is ...

a = 1/2

The horizontal offset inside parentheses is ...

-h = 1

h = -1

The vertical offset outside parentheses is ...

k = -3

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Find all solutions of the equation in the interval [0,2pi).

Setler79 [48]

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3 years ago

AB has coordinates A(-5,9) and B(7,- 7). Points P, Q, and I are collinear

VMariaS [17]

Answer:

$\overline{QT}$

Step-by-step explanation:

We want to find the coordinates of a certain point C(x,y) such that C divides $A(x_1,y_1)$ and $B(x_2,y_2)$ in the ratio m:n=3:2

The x-coordinate is given by:

$x=\frac{mx_2+nx_1}{m+n}$

The y-coordinate is given by:

$y=\frac{my_2+ny_1}{m+n}$

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We substitute the values to get:

$x=\frac{3*7+2*-5}{3+2}$

$x=\frac{21-10}{5}$

$x=\frac{11}{5}$

and

$y=\frac{3*-7+2*9}{3+2}$

$y=\frac{-21+18}{5}$

$y=-\frac{3}{5}$

Therefore C has coordinates $(\frac{11}{5},-\frac{3}{5})$

The line segment that contains C is $\overline{QT}$

See attachment.

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3 years ago

Find the midpoint of the line segment with the endpoints (1, 0) and (2, -10).

Mariulka [41]

Answer:

$\bigl(\frac{3}{2},-5\bigr)$

or in decimal form

$(1.5,-5)$

Step-by-step explanation:

The midpoint of the line with endpoints $(x_1,y_1)$ and $(x_2,y_2)$ is $\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)$ . just take the average between the points

so given the points (1,0) and (2,-10)

$x_1=1$

$y_1=0$

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the midpoint is found as follows:

$\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)$

$\bigl(\frac{1+2}{2},\frac{0-10}{2}\bigr)$

$\bigl(\frac{3}{2},\frac{-10}{2}\bigr)$

$\bigl(\frac{3}{2},-5\bigr)$

or in decimal form

$(1.5,-5)$

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3 years ago

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Sindrei [870]

Step-by-step explanation:

We need to find an expression for $\dfrac{\dfrac{-5}{6}}{\dfrac{-1}{3}}$ .

We can solve it as follows.

We know that,

$\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}$

So,

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or

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Hence, this is the required solution.

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steposvetlana [31]

Answer:

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Step-by-step explanation:

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