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3 years ago

When you graph a linear equation can you have a curve on the graph?

Mathematics

1 answer:

koban [17]3 years ago

4 0

Answer:

No, a linear function is a straight line, as the rate of change between the x and y values remains constant throughout the function. A quadratic, or a cubic function would have a "curve" in the graph.

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One spring day, Landon noted the time of day and the temperature, in degrees Fahrenheit. His findings are as follows: At 6 a.m.,

Verizon [17]

Answer:

Graph these points listed below

Step-by-step explanation:

Graph the following points:

(6 am, 50)

(9 am, 59)

(1 pm, 63)

(6 pm, 63)

(8 pm, 59)

(12 am midnight, 58)

6 0

2 years ago

Solve the equation for principal values of x. Express solutions in degrees.

Hitman42 [59]

Option C:

x = 90°

Solution:

Given equation:

$\sin x=1+\cos ^{2} x$

To find the degree:

$\sin x=1+\cos ^{2} x$

Subtract 1 + cos²x from both sides.

$\sin x-1-\cos ^{2} x=0$

Using the trigonometric identity: $\cos ^{2}(x)=1-\sin ^{2}(x)$

$\sin x-1-\left(1-\sin ^{2}x\right)=0$

$\sin x-1-1+\sin ^{2}x=0$

$\sin x-2+\sin ^{2}x=0$

$\sin ^{2}x+\sin x-2=0$

Let sin x = u

$u^2+u-2=0$

Factor the quadratic equation.

$(u+2)(u-1)=0$

u + 2 = 0, u – 1 = 0

u = –2, u = 1

That is sin x = –2, sin x = 1

sin x can't be smaller than –1 for real solutions. So ignore sin x = –2.

sin x = 1

The value of sin is 1 for 90°.

x = 90°.

Option C is the correct answer.

3 0

3 years ago

Read 2 more answers

100.00=137.76/(1+r)^5 solve for r thanks much

Feliz [49]

(1+r)^5=137.76/100
1+r=(137.76/100)^(1/5)
R=(137.76/100)^(1/5))-1

5 0

3 years ago

15, -19, 23, -27.. how would you write that in sigma notation?

sertanlavr [38]

Answer: i think its zero

Step-by-step explanation:

or u can just look it up on an sigma math calculator and that should give u the answer

3 0

2 years ago

Exam pls help 34 points

FrozenT [24]

Answer:

it would be 4/20 I thinkk

Step-by-step explanation:

4 0

3 years ago