I think all solution apply
Answer:
✨I think the answer is d.✨
Step-by-step explanation:
sorry if im wrong✨
Answer:
68% of jazz CDs play between 45 and 59 minutes.
Step-by-step explanation:
<u>The correct question is:</u> The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).
According to the 68-95-99.7 rule, what percentage of jazz CDs play between 45 and 59 minutes?
Let X = <u>playing time of jazz CDs</u>
SO, X ~ Normal()
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
Now, according to the 68-95-99.7 rule, it is stated that;
- 68% of the data values lie within one standard deviation points from the mean.
- 95% of the data values lie within two standard deviation points from the mean.
- 99.7% of the data values lie within three standard deviation points from the mean.
Here, we have to find the percentage of jazz CDs play between 45 and 59 minutes;
For 45 minutes, z-score is = = -1
For 59 minutes, z-score is = = 1
This means that our data values lie within 1 standard deviation points, so it is stated that 68% of jazz CDs play between 45 and 59 minutes.
Hello there,
From Point A to Point B Peter traveled roughly 30 miles in 30 minutes.
From Point B to Point C Peter traveled roughly 130 miles in 2 hours and 30 minutes.
From Point C he didn't move in distance but the hours moved so c is out.
From Point C to Point D, Peter traveled roughly 180 miles in 3 hours.
Therefore D Peter had the fastest interval at D.