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pishuonlain [190]
4 years ago
7

How do I set up this problem. I'm lost

Mathematics
1 answer:
Ivenika [448]4 years ago
7 0

Answer:

the answer is 64 .

Step-by-step explanation:

basically i just divided 48 by 2.4 and got 20 .. so that means that 20 has to be the multiplied factor so i just multiplied 3.2 by 20 and got 64.

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Can someone please help me????? Please I'm not good with Geometry
Otrada [13]

The hurdle and runner form a right triangle (see attached picture) such that

sin(30°) = <em>h</em> / (5 ft)

and

cos(30°) = <em>x</em> / (5 ft)

where <em>h</em> is the height of the hurdle and <em>x</em> is the horizontal distance from where the runner jumps to the hurdle. So

<em>h</em> = (5 ft) sin(30°) = 5/2 ft = 2.5 ft

<em>x</em> = (5 ft) cos(30°) = (5√3)/2 ft ≈ 4.33 ft

6 0
3 years ago
Is 4 33/100 a repeating decimal
Lisa [10]

Answer:

no

Step-by-step explanation:

4 33/100 is equal to 4.33, it is 4.33, not 4.33 with the dot on it, it means recurring decimal. It is jot a recurring decimal. :)

4 0
2 years ago
The volume of a gas varies directly with its temperature and inversely with the pressure. If the volume of a certain gas is 15 c
vladimir2022 [97]

Answer:

Therefore the volume of the gas is 32 cubic feet.

Step-by-step explanation:

Given that,

The volume of a gas varies directly with its temperature and inversely with the pressure.

V\propto \frac{T}{P}

V= Volume of the gas at constant mass

T= Temperature at constant mass

P= pressure at constant mass

\frac{V_1}{V_2}=\frac{\frac{T_1}{T_2}}{\frac{P_1}{P_2}}

\therefore \frac{V_1}{V_2}=\frac{T_1P_2}{T_2P_1}.

Given that,

At constant mass, the volume of a certain gas is 15 cubic feet and a pressure of 40 pound per square inch at a temperature 300 k.

V_1=15 cubic feet, P_1=40 pound per square inch and T_1= 300 K

V_2=?, P_2=20 pound per square inch and T_2= 320k

\therefore \frac{V_1}{V_2}=\frac{T_1P_2}{T_2P_1}.

Plugging all values

\frac{15}{V_2}=\frac{300\times 20}{320\times 40}

\Rightarrow V_2=\frac{15\times 320\times 40}{300\times 20}{}

\Rightarrow V_2=32 cubic feet

Therefore the volume of the gas is 32 cubic feet.

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3 years ago
6log8(3) - 3log8 (2)
ladessa [460]
Log - 46656
Decimal form - 4.66890750
7 0
3 years ago
Which number has the greatest value?<br><br> A) |23|<br><br> B) |-24|<br><br> C) 25<br><br> D) -26
enot [183]
C 25.................
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3 years ago
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