Answer:
$10,144.93
Step-by-step explanation:
Amount formula; A = (Principal* rate* time) +Principal
A= (P*r*t) +P
A= 14,000
r= 9.5% OR 0.095 as a decimal
t= 4
Plug the numbers into the formula;
14,000 = (P* 0.095 *4 ) +P
14,000 = 0.38P +P
14,000 = 1.38P
Divide both sides by 1.38 to solve for P;
14,000/1.38 = P
P= 10,144.9275
Therefore, the present value (Principal) = $10,144.93
Answer:
1+1=2-1=1
Step-by-step explanation:
lol, this is the hardest question I've done today.
Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)
first factor into (x-r1)(x-r2)... form
p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2
so
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real
baseically
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
Okay here's an example so if we have 2, 3/2*1/2 we convert the mixed numbers to improper fractions. So in order to solve a mixed number you add the denominator, numerator and whole to get 7/2*1.2
So Multiple
7/2*1/2
Refine the fractions
7/2*2
Multiple the numbers 2*2=4 to get
7/4
and that equals 1, 3/4
Answer:
The maximum height of the prism is 
Step-by-step explanation:
Let
x------> the height of the prism
we know that
the area of the rectangular base of the prism is equal to
so
-------> inequality A
------> equation B
-----> equation C
Substitute equation B in equation C
------> equation D
Substitute equation B and equation D in the inequality A
-------> using a graphing tool to solve the inequality
The solution for x is the interval---------->![[0,12]](https://tex.z-dn.net/?f=%5B0%2C12%5D)
see the attached figure
but remember that
The width of the base must be 
meters less than the height of the prism
so
the solution for x is the interval ------> ![(9,12]](https://tex.z-dn.net/?f=%289%2C12%5D)
The maximum height of the prism is
