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Nikitich [7]
3 years ago
7

Factor the greatest common factor. -30k^6 + 9k^5 - 21k^4

Mathematics
2 answers:
levacccp [35]3 years ago
7 0

Answer:

Since both terms are perfect squares, factor using the difference of squares formula,  

a

2

−

b

2

=

(

a

+

b

)

(

a

−

b

)

where  

a

=

k

2

and  

b

=

1

.

9

(

−

36

k

6

+

k

5

−

k

−

2

)

gulaghasi [49]3 years ago
3 0
The GCF is -3k^4
-30k^6+9k^5-21k^4= -3k^4(10k^2-3k+7)
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Answer:

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Step-by-step explanation:

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\Grace is 1.65 meters tall. At 3 p.m., she measures the length of a tree's shadow to be 25.35 meters. She stands 20.9 meters awa
Anika [276]

Grace's height and the tree's height are related by equivalent ratios

The height of the tree is 2.00 meters

Grace's height is given as:

\mathbf{h = 1.65}

When she measured the length of the tree's shadow, we have:

\mathbf{l = 20.9m} --- the length of her shadow

\mathbf{L = 25.35m} --- the length of the tree's shadow

The height (H) of the tree is calculated using the following equivalent ratio

\mathbf{h:H = l:L}

Substitute known values

\mathbf{1.65:H = 20.9:25.35}

Express as fractions

\mathbf{\frac H{1.65} =\frac{25.35}{20.9}}

Multiply both sides by 1.65

\mathbf{H=\frac{25.35}{20.9} \times 1.65}

Simplify

\mathbf{H=2.00}

Hence, the approximated height of the tree is 2.00 meters

Read more about equivalent ratios at:

brainly.com/question/13513438

5 0
3 years ago
Which graph represents f(x) =3(2)^x
boyakko [2]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
If a 100.8 kg cement bag had 20.35 kg removed from it, what is the new weight of the bag?
Snowcat [4.5K]
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8 0
3 years ago
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