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Answer:
0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
The standard deviation of the binomial distribution is:
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that ,
.
In this problem, we have that:
. So
Consider the probability that greater than 94 out of 153 people will not get the flu this winter
This probability is 1 subtracted by the pvalue of Z when X = 94. So
has a pvalue of 0.1788
1 - 0.1788 = 0.8212
0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.
The charity will receive $ 11
<h3><u>Solution:</u></h3>Ken earned $176 from his part-time job this summer
Amount earned = $ 176
He spent 25% of his money on games
Therefore,
Money spent on games = 176 - 25 % of 176
He is going to donate 1/4 of the remaining money to charity
Reamining amount = 176 - 132 = 44
Therefore,
Thus he gave $ 11 to charity