Answer:
5^3 y^5
125 y^5
Step-by-step explanation:
5y^3/(5y)^-2
Distribute the exponent in the denominator
5y^3/(5 ^-2 y^-2)
A negative exponent in the denominator brings it to the numerator
5y^3 5 ^2 y^2
Combine like terms
5 * 5^2 * y^3 5^2
We know that a^b * a^c = a^(b+c)
5^(1+2) * y^( 3+2)
5^3 y^5
125 y^5
Answer: £54.60
Step-by-step explanation:
7.80 x 7 = £54.60
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The total number of 13-card hands that can be dealt is 52C13. Four of these are of the same suit. Therefore the required probability is given by:
Answer:
S₃ = 37
Step-by-step explanation:
given a₁ = 16 and r = 
, then
a₂ = a₁ × = 16 × = 12
a₃ = a₂ × = 12 × = 9
then
S₃ = a₁ + a₂ + a₃ = 16 + 12 + 9 = 37
