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Licemer1 [7]
3 years ago
13

Aaden wants to get a subscription to an online library. There are two subscription options, one of which charges a fixed 96 doll

ar annual fee and the other which charges 3 dollars per book he borrows. Here's a graph that shows a system of equations for this scenario where x borrows and y is the total cost of the subscription Is the number of books Aaden borrows and y is the total cost of the subscription.What does point Q epresent in this context?
Mathematics
1 answer:
SSSSS [86.1K]3 years ago
3 0

Answer:

Since theres no graph I can't really help but if the graph shows that he borrows a lot of books every day then he should get the 96 dollar annual fee subscription but if he rarely borrows any books, let's say 1 or 2 months after his first borrow then it would be the 3 dollar subscription

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amm1812
The value of 4 is Hundreds.
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3 years ago
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Solve this equation for x. Round your answer to the nearest hundredth. 7 = ln(x + 3)​
Nesterboy [21]
E^7 = x +3
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6 0
3 years ago
Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
3 years ago
At a dinner, one meal cost $22 and a sales tax of $1.87 was added to the bill.
raketka [301]

Answer:

5.61; 8.5 %

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Tax = $1.87 per $22 meal

For a $66 meal,

Tax = 66 × 1.87/22

Tax = 3 × 1.87

Tax = $5.61

=====

Tax rate = 1.87/22 × 100

Tax rate = 0.085 × 100

Tax rate = 8.5 %

3 0
3 years ago
5/7 + 3/8?
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I don't know if anyone know say him answer

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