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myrzilka [38]
3 years ago
10

In a class of 30, 80 percent of students answered a question correctly. how many got it right?

Mathematics
1 answer:
aleksandrvk [35]3 years ago
5 0

Answer:

24

Step-by-step explanation:

Take the number of students and multiply by the percentage to see how many got it right

30 *80%

Change to decimal form

30 *.8 =24

24 students got it correct

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Find parametric equations for the path of a particle that moves along the circlex2 + (y − 3)2 = 16in the manner described. (Ente
AfilCa [17]

Answer:y=4

Step-by-step explanation:

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3 years ago
Distance formula for (3,-2) and (5,-3)
Soloha48 [4]

Answer:

d = 2.2

Step-by-step explanation:

Using the distance formula, you would plug in the numbers into the equation. d = √(5 - 3)^2 + ( -3 + 2)^2. So (5 - 3) is 2, and (-3 + 2) is -1. Then square both of the answers, and the equation becomes, d = √4 + 1. And that equals 5, so then you would find the square root, which would be approximately 2.2

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3 years ago
. Anna was thinking of a number. She told Bill that if he squared her number followed by subtracting 11 times her, and adding 4,
Snowcat [4.5K]

Answer:

Anna's number could be 5 and it could be 6.

Step-by-step explanation:

Let Anna's number be represented by x.

If Bill squared her number followed by subtracting 11 times her number, and adding 4, then he would get -26.

This implies that:

x^2 - 11x + 4 = -26

This is a quadratic equation and we can solve for x by factorization.

x^2 - 11x + 4 = -26\\\\=> x^2 - 11x + 4 + 26 = 0\\\\x^2 - 11x + 30 = 0\\\\x^2 -6x-5x + 30 = 0\\\\x(x - 6) - 5(x - 6) = 0\\\\(x - 5) (x - 6) = 0\\\\

=> x = 5 and x = 6

Anna's number could be 5 and it could be 6.

4 0
3 years ago
A quadratic function f(x)f(x) is hidden from view. You must find the xx-intercept(s) of f(x)f(x) and write the answer(s) in the
Alika [10]

f(x) should be in canonical form. So it must have the form

f(x)=a(x-x_v)^2+y_v

Where a is the main coefficient and is the vertex

Step-by-step explanation:

A quadratic function has a unique extreme value in its vertex. That value might be a maximum or a minimum depending on the sign of the main coefficient of the quadratic function. In order to quickly obtain the vertex, the quadratic must be written in canonical form. That means that f(x) must have the form

f(x)=a(x-x_v)^2+y_v

Where a is the main coefficient (which should be negative so that a minimum exists in the first place) and is the vertex. If f(x) is written in that form, then it will be easier to find the minimum of f(x), which is the vertex

Hence for the quadratic function below

\begin{gathered} f(x)=(x-2)^2-9 \\ f(x)=x^2-4x-5 \\ ax^2+bx+c \\ a=1,\text{ b=-4, c=-5} \\ x_v=-\frac{b}{2a} \\ x_v=\frac{-(-4)}{2(1)} \\ x_v=\frac{4}{2} \\ x_v=2 \\ y_v=2^2-4(2)-5 \\ y_v=-9 \\ (x,y)\longrightarrow(2,-9) \end{gathered}

Hence there is only one x- intercept and answer is (2, -9)

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2 years ago
Is 6.54 repeating a rational number?
kap26 [50]

Answer:

yes

Step-by-step explanation:

5 0
3 years ago
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