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OLga [1]
3 years ago
14

Find the ratio in which the line 2x + y – 4 = 0 divides the line segment joining A(2, -2) & B(3, 7)

Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer:

The required ratio is 2:9

Step-by-step explanation:

See the attachment below.

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F is an even function<br> a=<br> G is an odd function<br> b=
IrinaK [193]

Answer:

a = 6.34, b = 2.64

Step-by-step explanation:

used stat function on calculator

4 0
3 years ago
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What is the slope of the line that goes through the points (1,-5) and (4,1)
dem82 [27]

Answer:

D. 2

Step-by-step explanation:

So you use the formula with is \frac{y_{1}-y_{2}}{x_{1}-x_{2}}. so you get (1 - -5)/(4-1). this gets you to 6/3 and you get 2

5 0
2 years ago
Can Complementary angles be supplementary? <br> (Give me an explanation plss!!)
9966 [12]
For both complementary and supplementary angle...” No. For both complementary and supplementary angles, you can only have 2 angles and both of them must have positive measure. 1 or 3 or 4 angles can't be complementary or supplementary.
7 0
2 years ago
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Can you help with this one too.
lidiya [134]

Answer:

Odd, Even

Step-by-step explanation:

A function is said to be an Even function if it follows f(-x) = f(x).

A function is said to be an Odd function if it follows f(-x) = -f(x).

It means we can plug -x in place of x and check if it comes out to be f(x) or -f(x) i.e. y or -y?

Given y = sin³x/cos³x and y = 1/sec³x

y = sin^3x/cos^3x\\f(x) = sin^3x/cos^3x\\f(-x) = sin^3(-x)/cos^3(-x)\\f(-x)= (sin(-x))^3/(cos(-x))^3\\f(-x)=(-sin(x))^3/(cos(x))^3\\f(-x)=-sin^3x/cos^3x\\f(-x)=-f(x)\\Odd\; function

y=1/sec^3x\\f(x)= 1/sec^3x\\f(x)=cos^3x\\f(-x)=cos^3(-x)\\f(-x)=(cos(-x))^3\\f(-x)=(cos\;x)^3\\f(-x)=cos^3x\\f(-x)=f(x)\\Even\; function

Hence, first function is Odd, second function is Even.

3 0
2 years ago
What is larger  3/8  or  5/16
UkoKoshka [18]
\frac{3}{8} ... \frac{5}{16}

First, find the least common denominator between the two.
Since 8 is a factor of 16, the LCD is 16.

\frac{3*2}{8*2}

\frac{3}{8}=  \frac{6}{16}

Now, you can compare the numerators.

6>5

Since 6 is greater than 5, you know that \frac{6}{16} > \frac{5}{16}.

Therefore, we now know that \frac{3}{8} is larger.
7 0
3 years ago
Read 2 more answers
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