Question: What is the solution to 2x^2+8x=x^2-16?
Answer: x=-4 is what I got I'm not sure if u meant to put one of the 4's as -4 but yeah I got -4 and did it twice and got -4 again. Hope that helped.
Answer:
y=[-4]x+[10]
Step-by-step explanation:
For a line to be perpendicular to another it must have the reverse reciprocal of the opposite line, to find the reverse reciprocal you take your slope, flip the numerator and denominator, and multiply it by -1.
The slope
turns into
and is then multiplied by -1 to become
which can be simplified down to: 
Now that we know the slope we need the line to pass through a point, so we will use point slope form:

Substitute in our slope and point values:

Now solve for y:

Then you will find that line
runs perpendicular to
and intersects point (2,2).
2 different things
if it is
xy=k or if it is x/y=k
direct or inverse variation
I will do the x/y=k one
9/-12=-3/4
x=-4
-3/4=-4/y
mutiply both sides by y
-3/4y=-4
mutiply both sides by -4/3 to clear fraction
y=16/3