By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.
<h3>How to prove this point lies on the unit circle?</h3>
In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:
Reference angle = 180 - θ
Reference angle = 180 - 120
Reference angle = 60°.
For the coordinates, we have:
sin(-120) = -sin(60) = -1/2.
cos(-120) = -cos(60) = -√3/2.
By applying Pythagorean theorem, we have:
z² = x² + y²
z = √((-1/2)² + (-√3/2)²)
z = √(1/4 + 3/4)
z = √1
z = 1.
Read more on unit circle here: brainly.com/question/9797740
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So the equation you would make is 63 / 9 = width
This is because the formula of finding the area of a rectangle is <em>l </em>x <em>w = a</em>.
So since we already know the length and area, we just plug them in and switch up the formula to find the width.
If 9 (length) x ? (width) = 63 (area), then 63 / 9 = ? (width)
If you calculate it in your mind or even a calculator, you will find that 63 / 9 = 7.
Therefore the width of the rectangle is 7.
Answer:
a i think im sorry if wrong