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Kazeer [188]
4 years ago
5

Explain what the solution to a system of equations is:

Mathematics
1 answer:
WINSTONCH [101]4 years ago
3 0
A solution to a system of equations is a set of values for the variable that satisfy all the equations simultaneously. In order to solve a system of equations, one must find all the sets of values of the variables that constitutes solutions of the system.
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You have $250,000 in an IRA individual Retirement Account at the time you retire. You have the option this money in two funds: F
love history [14]
So to start off with this problem, let us call the amount invested in Plan A and B as a and b respectively.

So equation 1: a + b = 250,000

Next, we need to get an equation which is equal to 10,000. So the interest rate in plan a + interest rate in plan b would be equal to 10,000. Rewriting this sentence will give us:

Equation 2: .028a + 0.078b = 10,000

Rewrite the first equation into a = 250,000 - b, and then plug the value into equation 2.

.028(250,000 - b) + 0.078b = 10,000

7,000 - 0.028b + 0.078b = 10,000
-0.028b + 0.078b = 10,000 - 7,000
0.05b = 3,000
b = $60000 amount invested at 2.8% while 
250,000 - 60,000 = $190,000 is the amount invested at 7.8%

3 0
3 years ago
Show the correct way to write the numerical expression of 3×14+9
Sergio039 [100]

Answer:

(3 x 14) + 9

Step-by-step explanation:

4 0
4 years ago
Alguien puede ayudarme con esto por favor necesito el procedimiento ​
sasho [114]

en la primera

es -2x+7=13, suma 13 con 7 para q tengas 20 y el negativo dos x es la otra asi agarras -2=20 ahora dividelo los dos por 2 te sale 0 para el negativo dos y divide 20/2 son X=10

5 0
4 years ago
Find an ordered pair for 4 solution for -5x+y=6
grin007 [14]

⇒ Choose three values for x and substitute in to find the corresponding y values.

(0,6),(1,11),(2,16)

3 0
3 years ago
Find the zeros of the function in the interval (-2 pie, 2 pie). f(x) = 3 cos x
Fantom [35]

Answer:

<u>Roots</u><u> </u><u>are</u><u> </u><u>-</u><u>π</u><u>/</u><u>2</u><u> </u><u>and</u><u> </u><u>π</u><u>/</u><u>2</u>

Step-by-step explanation:

{ \bf{f(x) = 3 \cos(x) }}

when x is -2π:

{ \sf{f( - 2\pi) = 3 \cos( - 2\pi) }} \\ { \sf{ = 3}}

hence -2π is not a zero of the function

when x is 2π:

{ \sf{f(2\pi) = 3 \cos(2\pi) }} \\ { \sf{ = 3}}

hence 2π is not a zero of the function

when x is π/2:

{ \sf{f( \frac{\pi}{2}) = 3 \cos( \frac{\pi}{2} )  }} \\ { \sf{ = 0}}

Hence ±π/2 is the zero of the function.

4 0
3 years ago
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