Answer:
Theorem: The diagonals of a parallelogram bisect each other. Proof: Given ABCD, let the diagonals AC and BD intersect at E, we must prove that AE ∼ = CE and BE ∼ = DE. The converse is also true: If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.
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Answer:
C.
Step-by-step explanation:
Answer:
Two doesn’t equal 8. Theoretically, eight is the solution...
Step-by-step explanation:
H= .6.5
V=<span>πr^2h
h= v/</span>πr^2 = 2940.5/<span>π*12^2 = 6.49993 = 6.5</span>
Answer:
it doesnot give clear view