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butalik [34]
4 years ago
8

*EASY 7 GRADE MATH*

Mathematics
1 answer:
mezya [45]4 years ago
6 0

Step-by-step explanation:

see this image

thank you

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A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then
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Total marbles = 2 + 7 = 9

P(Purple, then white) = (7/9)(2/8) = 7/36

Answer: 7/36
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3 years ago
Which of the following represents a possible combination of books that Derek can buy?
Papessa [141]
It is most likely C if I am looking at it in need more information but if it is not C it is B
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The mass of an ant is 1/10 of the load, which it can carry in one try. What is the mass of the ant, if in one time it can carry
Viefleur [7K]

If you call m the mass of the ant and l the load, we have the equation

m = \cfrac{l}{10}

In fact, the mass of the ant is one tenth of the load, which is exactly what this equation states.

Since we are given the load, we simply need to plug its value in the equation to deduce the mass of the ant:

m = \cfrac{\frac{7}{250}}{10} = \cfrac{7}{250}\cdot\cfrac{1}{10} = \cfrac{7}{2500}

8 0
4 years ago
A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e
Elodia [21]

Answer:

The critical value for this hypothesis test is 6.571.

Step-by-step explanation:

In this case the professor wants to determine whether the average number of minutes that a student needs to complete a statistics exam has a standard deviation that is less than 5.0 minutes.

Then the variance will be, \sigma^{2}=(5.0)^{2}=25

The hypothesis to determine whether the population variance is less than 25.0 minutes or not, is:

<em>H</em>₀: The population variance is not less than 25.0 minutes, i.e. <em>σ²</em> = 25.

<em>Hₐ</em>: The population variance is less than 25.0 minutes, i.e. <em>σ²</em> < 25.

The test statistics is:

\chi ^{2}_{cal.}=\frac{ns^{2}}{\sigma^{2}}

The decision rule is:

If the calculated value of the test statistic is less than the critical value, \chi^{2}_{n-1} then the null hypothesis will be rejected.

Compute the critical value as follows:

\chi^{2}_{(1-\alpha), (n-1)}=\chi^{2}_{(1-0.05),(15-1)}=\chi^{2}_{0.95, 14}=6.571

*Use a chi-square table.

Thus, the critical value for this hypothesis test is 6.571.

7 0
4 years ago
Read 2 more answers
Evaluate the sum of the finite geometric series<br> 3 + 6 + 12 + 24 + 48 + . . . + 768
Wittaler [7]
<span>3 + 6 + 12 + 24 + 48 + . . . + 768
= 1533</span>
3 0
4 years ago
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