Answer:
$6.00
Explanation:
Given data
quantity demanded ( x ) ∝ 1 / p^3 for p > 1
when p = $10/unit , x = 64
initial cost = $140, cost per unit = $4
<u>Determine the price that will yield a maximum profit </u>
x = k/p^3 ----- ( 1 ). when x = 64 , p = $10 , k = constant
64 = k/10^3
k = 64 * ( 10^3 )
= 64000
back to equation 1
x = 64000 / p^3
∴ p = 40 / ∛x
next calculate the value of revenue generated
Revenue(Rx) = P(price ) * x ( quantity )
= 40 / ∛x * x = 40 x^2/3
next calculate Total cost of product
C(x) = 140 + 4x
Maximum Profit generated = R(x) - C(x) = 0
= 40x^2/3 - 140 + 4x = 0
= 40(2/3) x^(2/3 -1) - 0 - 4 = 0
∴ ∛x = 20/3 ∴ x = (20/3 ) ^3 = 296
profit is maximum at x(quantity demanded ) = 296 units
hence the price that will yield a maximum profit
P = 40 / ∛x
= ( 40 / (20/3) ) = $6
Answer:
D.$54,000
Explanation:
A flexible budget is a one which changes or adjusts with change in actual activity. The flexible amount is more reliable than the static amount. The static budget is one which is not adjusted with level of real activity. The machine hours are used as basis of adjustment for flexible budget. The amount of fixed overhead budgeted allocation cost is adjusted based on machine hours according to actual machine hours of 985 hours.
Answer:
Make since the relevant cost to make it is $59.05
Explanation:
Calculation to determine what Epsilon should choose to:
Relevant costs to make = 8.20 + 24.20 + [41*(100%-35%)]
Relevant costs to make = 8.20 + 24.20 + (41*65%)
Relevant costs to make = 8.20 + 24.20 + 26.65
Relevant costs to make =$59.05
Therefore Epsilon should choose to: MAKE SINCE THE RELEVANT COST TO MAKE IT IS $59.05
Answer:
well l'm not on instagram
