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horrorfan [7]
3 years ago
6

Write the statement “Mammals are animals that breathe air” in if-then form.

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
8 0
If the animal breaths air, then it is considered a mammal.

Currently it is written as a simple statement, rewriting it in the if-then form makes it a hypothesis more so.

Thus, this is how you would write the statement in if-then form.

Hope this helps!
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Last month, the daily balance in Joana's credit card account was $1,000 for 9 days, $750 for 10 days, $850 for 4 days, and $900
FrozenT [24]

Answer:

<em />Average = \$873<em />

<em />

Step-by-step explanation:

Given

$1000 for 9 days

$750 for 10 days

$850 for 4 days

$900 for other days

Required

Compute the daily average

First, we need to compute the number of days her balance is $900

Assuming the billing cycle is 30 days;

Number\ of\ days = 30 - (9 + 10 + 4)

Number\ of\ days = 30 - 23

Number\ of\ days = 7

The Average is then calculates using:

Average = \frac{\sum fx}{x}

Average = \frac{1000 * 9 + 750 * 10 + 850 * 4 + 900 * 7}{9 + 10 + 4+ 7}

Average = \frac{26200}{30}

Average = 873.333333333

<em />Average = \$873<em> --- Approximated</em>

3 0
3 years ago
If EFGH is a rectangle, what is FH?
lys-0071 [83]
I believe FH would be a line segment.
Hope this helps!
3 0
3 years ago
Help me!!!!!!!!!!! Help help help
kakasveta [241]

Answer:

5 × \frac{1}{100}

Step-by-step explanation:

4*100+2*10+3*1+6*\frac{1}{10}+x+9*\frac{1}{1000}=423.659\\4*100+2*10+3*1+6*0.1+x+9*0.001=423.659\\400+20+3+0.6+x+0.009=423.659\\423.609+x=423.659\\x=0.05\\\\50*\frac{1}{10}=5\\\\5*\frac{1}{100}=0.05\\\\50=50\\\\5*0.05=0.25

8 0
3 years ago
Section 5.2 Problem 17:
Elina [12.6K]

This DE has characteristic equation

4r^2 - 12r + 9r = (2r - 3)^2 = 0

with a repeated root at r = 3/2. Then the characteristic solution is

y_c = C_1 e^{\frac32 x} + C_2 x e^{\frac32 x}

which has derivative

{y_c}' = \dfrac{3C_1}2 e^{\frac32 x} + \dfrac{3C_2}2 x e^{\frac32x} + C_2 e^{\frac32 x}

Use the given initial conditions to solve for the constants:

y(0) = 3 \implies 3 = C_1

y'(0) = \dfrac52 \implies \dfrac52 = \dfrac{3C_1}2 + C_2 \implies C_2 = -2

and so the particular solution to the IVP is

\boxed{y(x) = 3 e^{\frac32 x} - 2 x e^{\frac32 x}}

8 0
2 years ago
Helpp! im 2 lazy to do it
LUCKY_DIMON [66]

Answer:

28. add them all together

5 0
2 years ago
Read 2 more answers
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